3q^2-17q-28=0

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Solution for 3q^2-17q-28=0 equation:


Simplifying
3q2 + -17q + -28 = 0

Reorder the terms:
-28 + -17q + 3q2 = 0

Solving
-28 + -17q + 3q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(-4 + -3q)(7 + -1q) = 0

Subproblem 1

Set the factor '(-4 + -3q)' equal to zero and attempt to solve: Simplifying -4 + -3q = 0 Solving -4 + -3q = 0 Move all terms containing q to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -3q = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -3q = 0 + 4 -3q = 0 + 4 Combine like terms: 0 + 4 = 4 -3q = 4 Divide each side by '-3'. q = -1.333333333 Simplifying q = -1.333333333

Subproblem 2

Set the factor '(7 + -1q)' equal to zero and attempt to solve: Simplifying 7 + -1q = 0 Solving 7 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1q = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1q = 0 + -7 -1q = 0 + -7 Combine like terms: 0 + -7 = -7 -1q = -7 Divide each side by '-1'. q = 7 Simplifying q = 7

Solution

q = {-1.333333333, 7}

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